main.py

import Hashingalgo.Hashing as hashed
import Sql.connsql as sqldb
import hashlib

print(hashed.hashpassword("test"))
#prints 7271985111664709
print(hashed.hashpassword("test1"))
# prints 7273835519420423
print(hashed.hashpassword("Iloveashley"))
# prints 11149784805523827

# the user user creates a new account with the password
#                   "Iloveashley"
# When user sets the passwords, the password is hashed and stored as
#                   11149784805523827
sqldb.checkpassword( idnum= 1 , currentpass="Iloveashley" )
# The server hashes the "Iloveashley", then sends the hash
#               11149784805523827
# to the database to check if it is the same and returns true or false

# Hashes get more and more complicated, adding new steps to the hasing algorithm
# taking the hashed number and turning into a hexadedecimal would be a good start
# *Using a real life but outdated hashing algorthm from the hashlib*
hashedlevel1 = hash("test")
print(hashedlevel1)
# prints            -69210052664837847
hashedlevel2 = hex(hash(hashedlevel1))
print(hashedlevel2)
# prints            0x2d9d101740746680
hashedlevel3 = hash(hashedlevel2.split("x")[1])
print(hashedlevel3)
#prints             4252262274784329667

# as we can see by adding a few steps, the password "test" was converted to 4252262274784329667
# if we add a few more complex steps to this, it would take some time for a good mathematician to figure out the hash
# Hashes are not made to be "reversed", from 4252262274784329667 we shouldnt be able to get "test"