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正则表达式 #23

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Yang03 opened this issue Aug 21, 2018 · 0 comments

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Yang03 commented Aug 21, 2018 •

edited

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前向声明

?=
'abcacad'.replace(/a(?=b)/g,'*') //*bcacad

反前向声明

'abcacad'.replace(/a(?!b)/g,'*') //abc*c*d

let str="123456789";
let  re=/(?=(?!(\b))(\d{3})+$)/g
str=str.replace(re, ",")
console.log(str)

\b 是单词边界

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