-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy path2024.4.18.c
165 lines (157 loc) · 2.59 KB
/
2024.4.18.c
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#include<stdbool.h>
//求集合的并集、交集、差集
typedef struct arr3
{
int array[1000];
int n;
}arr;
bool check(arr arr3, int number)
{
int i = 0;
for (i = 0; i < arr3.n; i++)
{
if (arr3.array[i] == number)
{
return true;
}
}
return false;
}
arr add(int* arr1, int n1, int* arr2, int n2)
{
int i = 0;
arr arr3;
arr3.n = 0;
for (i = 0; i<n1; i++)
{
arr3.array[i] = arr1[i];
arr3.n++;
}
int j = i;
for (i = 0; i < n2; j++, i++)
{
bool flag = check(arr3, arr2[i]);
if (flag)
{
continue;
}
arr3.array[arr3.n] = arr2[i];
arr3.n++;
}
return arr3;
}
bool find(int number, int* arr2, int n2)
{
int i = 0;
for (i = 0; i < n2; i++)
{
if (arr2[i] == number)
{
return true;
}
}
return false;
}
arr inarr(int* arr1, int n1, int* arr2, int n2)
{
int i = 0;
arr arr4;
arr4.n = 0;
for (i = 0; i < n1; i++)
{
if (find(arr1[i], arr2, n2))
{
arr4.array[arr4.n] = arr1[i];
arr4.n++;
}
}
return arr4;
}
bool checknode(int number, int* arr2, int n2)
{
int i = 0;
for (i = 0; i < n2; i++)
{
if (arr2[i] == number)
{
return true;
}
}
return false;
}
arr chaarr(int* arr1, int n1, int* arr2, int n2)
{
arr arr5;
arr5.n = 0;
int i = 0;
for (i = 0; i < n1; i++)
{
if (checknode(arr1[i], arr2, n2))
{
continue;
}
arr5.array[arr5.n] = arr1[i];
arr5.n++;
}
return arr5;
}
int main()
{
printf("输入集合a的大小\n");
int n1;
scanf("%d", &n1);
int* arr1 = NULL;
arr1 = (int*)malloc(sizeof(int) * n1);
if (arr1 == NULL)
{
printf("NULL\n");
return -1;
}
printf("输入集合a的元素\n");
int i = 0;
for (i = 0; i < n1; i++)
{
scanf("%d", &arr1[i]);
}
printf("输入集合b的大小\n");
int n2;
scanf("%d", &n2);
int* arr2 = NULL;
arr2 = (int*)malloc(sizeof(int) * n2);
if (arr2 == NULL)
{
printf("NULL\n");
return -1;
}
printf("输入集合b的元素\n");
int j = 0;
for (j = 0; j < n2; j++)
{
scanf("%d", &arr2[j]);
}
//求并集
arr addarray = add(arr1, n1, arr2, n2);
printf("两个集合的并集是\n");
for (i = 0; i < addarray.n; i++)
{
printf("%d ", addarray.array[i]);
}
printf("\n");
arr inarray = inarr(arr1, n1, arr2, n2);
printf("两个集合的交集是\n");
for (i = 0; i < inarray.n; i++)
{
printf("%d ", inarray.array[i]);
}
printf("\n");
arr chaarray = chaarr(arr1, n1, arr2, n2);
printf("两个集合的差集是\n");
for (i = 0; i < chaarray.n; i++)
{
printf("%d ", chaarray.array[i]);
}
return 0;
}