OddEvenStringSort.js

// Given a string s. You have to return another string such that even-indexed and odd-indexed characters of s are grouped and groups are space-separated (see sample below)

// Note: 
// 0 is considered to be an even index. 
// All input strings are valid with no spaces


function sortMyString(S) {
    // your code here
  return S.split("").filter((elem,i)=> i%2 === 0).join("") + " " + S.split("").filter((elem,i)=> i%2 !== 0).join("")
    
}