Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You must write an algorithm with
Example 1:
Input: nums = [1,3,5,6], target = 5
Output: 2
Example 2:
Input: nums = [1,3,5,6], target = 2
Output: 1
Example 3:
Input: nums = [1,3,5,6], target = 7
Output: 4
Constraints:
1 <= nums.length <= 10^4
-10^4 <= nums[i] <= 10^4
nums
contains distinct values sorted in ascending order.-10^4 <= target <= 10^4
- Thursday, 3 March, 2022
- Time Complexity:
$O(\log n)$ - Space Complexity:
$O(1)$ - Runtime: 52 ms, faster than 83.99% of Python3 online submissions for Search Insert Position.
- Memory Usage: 14.9 MB, less than 49.16% of Python3 online submissions for Search Insert Position.
class Solution:
def searchInsert(self, nums: List[int], target: int) -> int:
l = 0
r = len(nums) - 1
while l <= r:
mid = l + ((r - l) >> 1);
if nums[mid] < target:
l = mid + 1
elif nums[mid] > target:
r = mid - 1
else:
return mid
return l