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Copy path54.螺旋矩阵-1.cpp
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54.螺旋矩阵-1.cpp
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/*
* @lc app=leetcode.cn id=54 lang=cpp
*
* [54] 螺旋矩阵
*/
// 官方方法 1
// @lc code=start
class Solution {
private:
static constexpr int directions[4][2] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};
public:
vector<int> spiralOrder(vector<vector<int>> &matrix) {
if (matrix.size() == 0 || matrix[0].size() == 0) {
return {};
}
int rows = matrix.size(), columns = matrix[0].size();
vector<vector<bool>> visited(rows, vector<bool>(columns));
int total = rows * columns;
vector<int> order(total);
int row = 0, column = 0;
int directionIndex = 0;
for (int i = 0; i < total; i++) {
order[i] = matrix[row][column];
visited[row][column] = true;
int nextRow = row + directions[directionIndex][0], nextColumn = column + directions[directionIndex][1];
if (nextRow < 0 || nextRow >= rows || nextColumn < 0 || nextColumn >= columns || visited[nextRow][nextColumn]) {
directionIndex = (directionIndex + 1) % 4;
}
row += directions[directionIndex][0];
column += directions[directionIndex][1];
}
return order;
}
};
// @lc code=end