We read every piece of feedback, and take your input very seriously.
To see all available qualifiers, see our documentation.
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
group2
compare_means()
When the group1 name is group2 compare_means() error
require(ggpubr) tribble( ~val, ~gp, ~by, 923 , 'group4','V1', 1252, 'group4','V1', 1442, 'group4','V1', 1398, 'group2','V1', 1858, 'group2','V1', 1330, 'group2','V1', 2593, 'group2','V1', 23 , 'group4','V2', 252, 'group4','V2', 442, 'group4','V2', 398, 'group2','V2', 858, 'group2','V2', 330, 'group2','V2', 593, 'group2','V2' ) %>% dplyr::mutate(gp=factor(gp, levels = c('group2','group4'))) -> dat ggpubr::compare_means(formula = val ~ gp, data = dat, group.by = 'by', paired = F) ggpubr:::.test_pairwise(dat, formula = val ~ gp) Error: Problem with `mutate()` input `p`. x Problem with `filter()` input `..1`. x Input `..1` must be of size 1, not size 0. ℹ Input `..1` is `!is.na(p)`. ℹ Input `p` is `purrr::map(...)`.
ggppubr:::.test_pairwise
.test_pairwise2 <- function (data, formula, method = "wilcox.test", paired = FALSE, pool.sd = !paired, ...) { x <- deparse(formula[[2]]) group <- attr(stats::terms(formula), "term.labels") if (ggpubr:::.is_empty(group)) { res <- .test(data, formula, method = method, ...) return(res) } method <- switch(method, t.test = "pairwise.t.test", wilcox.test = "pairwise.wilcox.test") test <- match.fun(method) test.opts <- list(x = ggpubr:::.select_vec(data, x), g = ggpubr:::.select_vec(data,group), paired = paired) if (method == "pairwise.t.test") { if (missing(pool.sd)) { if (!paired) pool.sd <- FALSE } test.opts$pool.sd <- pool.sd } pvalues <- suppressWarnings(do.call(test, test.opts)$p.value) %>% as.data.frame() group1 <- group2 <- p <- NULL pvalues$.group2 <- rownames(pvalues) pvalues <- pvalues %>% tidyr::gather( key = "group1", value = "p", -.group2) %>% dplyr::select(group1, group2=.group2, p) %>% dplyr::filter(!is.na(p)) pvalues } # .group2 temp name .test_pairwise2(dat, formula = val ~ gp) group1 group2 p 1 group2 group4 0.3449883
The text was updated successfully, but these errors were encountered:
ecaebfb
No branches or pull requests
When the group1 name is
group2
compare_means()
errorggppubr:::.test_pairwise
The text was updated successfully, but these errors were encountered: