In 'a&b=' treat a as boolean flag (true)

[scharf]

If no = is given for a flag, it should be handled as boolean (true).

For example:

Qs.parse('a&b=', {allowBoolean: true});
//  {a: true, b: ''}

without the allowBoolean option, it should not do this conversion (as it does today):

Qs.parse('a&b=');
//  {a: '', b: ''}

[pierot]

I would argue that the other way around, giving a null as value for a key, should generate a querystring value without the =.

Qs.stringify({a: null, b: "test"});
// ?a&b=test

Empty string could still behave as it is doing right now:

Qs.stringify({a: null, b: "test", c: ""});
// ?a&b=test&c=

[scharf]

@pierot That makes a lot of sense!

Else the following assertion fails:

assert.deepEqual(
    Qs.parse(Qs.stringify({a: null, b: "test", c: ""})),  // a=&b=test&c=
    {a: null, b: "test", c: ""}                           // {a: "", b: "test", c: ""} 
);

[pierot]

I made a pull request for this: #85

[nlf]

Closed via #85