Balanced strings are those who have equal quantity of 'L' and 'R' characters.
Given a balanced string s
split it in the maximum amount of balanced strings.
Return the maximum amount of splitted balanced strings.
Example 1:
Input: s = "RLRRLLRLRL" Output: 4 Explanation: s can be split into "RL", "RRLL", "RL", "RL", each substring contains same number of 'L' and 'R'.
Example 2:
Input: s = "RLLLLRRRLR" Output: 3 Explanation: s can be split into "RL", "LLLRRR", "LR", each substring contains same number of 'L' and 'R'.
Example 3:
Input: s = "LLLLRRRR" Output: 1 Explanation: s can be split into "LLLLRRRR".
Example 4:
Input: s = "RLRRRLLRLL" Output: 2 Explanation: s can be split into "RL", "RRRLLRLL", since each substring contains an equal number of 'L' and 'R'
Constraints:
1 <= s.length <= 1000
s[i] = 'L' or 'R'
Related Topics:
String, Greedy
// OJ: https://leetcode.com/problems/split-a-string-in-balanced-strings/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int balancedStringSplit(string s) {
int cnt = 0, ans = 0;
for (int i = 0; i < s.size(); ++i) {
cnt += s[i] == 'L' ? 1 : -1;
if (cnt == 0) ++ans;
}
return ans;
}
};