Given a binary tree, return the sum of values of nodes with even-valued grandparent. (A grandparent of a node is the parent of its parent, if it exists.)
If there are no nodes with an even-valued grandparent, return 0
.
Example 1:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5] Output: 18 Explanation: The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.
Constraints:
- The number of nodes in the tree is between
1
and10^4
. - The value of nodes is between
1
and100
.
Related Topics:
Tree, Depth-first Search
// OJ: https://leetcode.com/problems/sum-of-nodes-with-even-valued-grandparent/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
int ans = 0;
vector<TreeNode*> v;
void preorder(TreeNode *root, int level) {
if (!root) return;
if (v.size() <= level) v.push_back(root);
else v[level] = root;
if (level - 2 >= 0 && v[level - 2]->val % 2 == 0) ans += root->val;
preorder(root->left, level + 1);
preorder(root->right, level + 1);
}
public:
int sumEvenGrandparent(TreeNode* root) {
preorder(root, 0);
return ans;
}
};