Given a string s
consisting only of letters 'a'
and 'b'
. In a single step you can remove one palindromic subsequence from s
.
Return the minimum number of steps to make the given string empty.
A string is a subsequence of a given string, if it is generated by deleting some characters of a given string without changing its order.
A string is called palindrome if is one that reads the same backward as well as forward.
Example 1:
Input: s = "ababa" Output: 1 Explanation: String is already palindrome
Example 2:
Input: s = "abb" Output: 2 Explanation: "abb" -> "bb" -> "". Remove palindromic subsequence "a" then "bb".
Example 3:
Input: s = "baabb" Output: 2 Explanation: "baabb" -> "b" -> "". Remove palindromic subsequence "baab" then "b".
Example 4:
Input: s = "" Output: 0
Constraints:
0 <= s.length <= 1000
s
only consists of letters 'a' and 'b'
Related Topics:
String
// OJ: https://leetcode.com/problems/remove-palindromic-subsequences/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int removePalindromeSub(string s) {
if (s.empty()) return 0;
bool isPalindrome = true;
for (int i = 0, j = s.size() - 1; i < j && isPalindrome; ++i, --j) {
isPalindrome = s[i] == s[j];
}
return isPalindrome ? 1 : 2;
}
};