You are given an m x n
integer grid accounts
where accounts[i][j]
is the amount of money the ith
customer has in the jth
bank. Return the wealth that the richest customer has.
A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Example 1:
Input: accounts = [[1,2,3],[3,2,1]] Output: 6 Explanation:1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]] Output: 10 Explanation: 1st customer has wealth = 6 2nd customer has wealth = 10 3rd customer has wealth = 8 The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17
Constraints:
m == accounts.length
n == accounts[i].length
1 <= m, n <= 50
1 <= accounts[i][j] <= 100
// OJ: https://leetcode.com/problems/richest-customer-wealth/
// Author: github.com/lzl124631x
// Time: O(MN)
// Space: O(1)
class Solution {
public:
int maximumWealth(vector<vector<int>>& A) {
int ans = 0;
for (auto &row : A) ans = max(ans, accumulate(begin(row), end(row), 0));
return ans;
}
};