You are given a 0-indexed 2D integer array questions
where questions[i] = [pointsi, brainpoweri]
.
The array describes the questions of an exam, where you have to process the questions in order (i.e., starting from question 0
) and make a decision whether to solve or skip each question. Solving question i
will earn you pointsi
points but you will be unable to solve each of the next brainpoweri
questions. If you skip question i
, you get to make the decision on the next question.
- For example, given
questions = [[3, 2], [4, 3], [4, 4], [2, 5]]
:<ul> <li>If question <code>0</code> is solved, you will earn <code>3</code> points but you will be unable to solve questions <code>1</code> and <code>2</code>.</li> <li>If instead, question <code>0</code> is skipped and question <code>1</code> is solved, you will earn <code>4</code> points but you will be unable to solve questions <code>2</code> and <code>3</code>.</li> </ul> </li>
Return the maximum points you can earn for the exam.
Example 1:
Input: questions = [[3,2],[4,3],[4,4],[2,5]] Output: 5 Explanation: The maximum points can be earned by solving questions 0 and 3. - Solve question 0: Earn 3 points, will be unable to solve the next 2 questions - Unable to solve questions 1 and 2 - Solve question 3: Earn 2 points Total points earned: 3 + 2 = 5. There is no other way to earn 5 or more points.
Example 2:
Input: questions = [[1,1],[2,2],[3,3],[4,4],[5,5]] Output: 7 Explanation: The maximum points can be earned by solving questions 1 and 4. - Skip question 0 - Solve question 1: Earn 2 points, will be unable to solve the next 2 questions - Unable to solve questions 2 and 3 - Solve question 4: Earn 5 points Total points earned: 2 + 5 = 7. There is no other way to earn 7 or more points.
Constraints:
1 <= questions.length <= 105
questions[i].length == 2
1 <= pointsi, brainpoweri <= 105
Related Topics:
Array, Dynamic Programming
Similar Questions:
// OJ: https://leetcode.com/problems/solving-questions-with-brainpower/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
long long mostPoints(vector<vector<int>>& A) {
int N = A.size();
vector<long> dp(N + 2);
for (int i = 0; i < N; ++i) {
dp[i + 1] = max(dp[i + 1], dp[i]);
int next = min(i + A[i][1] + 2, N + 1);
dp[next] = max(dp[next], dp[i + 1] + A[i][0]);
}
return dp[N + 1];
}
};
Or
// OJ: https://leetcode.com/problems/solving-questions-with-brainpower/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
long long mostPoints(vector<vector<int>>& A) {
int N = A.size();
vector<long> dp(N + 1);
for (int i = N - 1; i >= 0; --i) {
dp[i] = max(dp[i], dp[i + 1]);
int next = min(i + A[i][1] + 1, N);
dp[i] = max(dp[i], dp[next] + A[i][0]);
}
return dp[0];
}
};