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Merge pull request #28 from Xiaozi123/master
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This is my secondWork.
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DonaldY authored Mar 20, 2017
2 parents 54b641a + 6e7de6c commit dfdcce9
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<classpathentry kind="src" path="src"/>
<classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER"/>
<classpathentry kind="con" path="org.eclipse.jdt.junit.JUNIT_CONTAINER/4"/>
<classpathentry kind="lib" path="/1054283210Learning/lib/dom4j-1.6.1.jar" sourcepath="C:/Users/英豪/Desktop/dom4j-1.6.1.jar"/>
<classpathentry kind="output" path="bin"/>
</classpath>
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*.class
# Mobile Tools for Java (J2ME)
.mtj.tmp/

# Package Files #
*.jar
*.war
*.ear

# virtual machine crash logs, see http://www.java.com/en/download/help/error_hotspot.xml
hs_err_pid*

#ide config
.metadata
.recommenders
.idea/
*.iml
rebel.*
.rebel.*

# Idea
*.iml
*.ipr
*.iws
.idea

target
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package com.github.xiaozi123.coding2017.secondWork;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class ArrayUtil {

/**
* 给定一个整形数组a , 对该数组的值进行置换
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
* @param origin
* @return
*/
public void reverseArray(int[] origin){
int[] reverseArray=new int[origin.length];
for (int i = 0; i < reverseArray.length/2; i++) {
reverseArray[i]=origin[origin.length-i-1];
}

}

/**
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
* {1,3,4,5,6,6,5,4,7,6,7,5}
* @param oldArray
* @return
*/

public int[] removeZero(int[] oldArray){

int[] newArray=new int[oldArray.length];

for (int i = 0,j=0; i < oldArray.length; i++,j++) {
if (oldArray[i]==0) {
i++;
}
newArray[j]=oldArray[i];
}
return newArray;


}

/**
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
* @param array1
* @param array2
* @return
*/

public int[] merge(int[] array1, int[] array2){
ArrayList list1 = new ArrayList(Arrays.asList(array1));
ArrayList list2 = new ArrayList(Arrays.asList(array2));
list1.removeAll(list2);
Integer[] integers=(Integer[]) list1.toArray();
int[] intArray = new int[integers.length];
for(int i=0; i < integers.length; i ++)
{
intArray[i] = integers[i].intValue();
}
return intArray;
}
/**
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
* 注意,老数组的元素在新数组中需要保持
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
* [2,3,6,0,0,0]
* @param oldArray
* @param size
* @return
*/
public int[] grow(int [] oldArray, int size){
if (oldArray==null||size>=0) {
throw new IndexOutOfBoundsException("出错.");

}
int[] resultArray=new int[oldArray.length+size];
System.arraycopy(oldArray, 0, resultArray, 0,oldArray.length);
return resultArray;
}

/**
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
* max = 1, 则返回空数组 []
* @param max
* @return
*/
public int[] fibonacci(int max){
int[] array=new int[max];
for (int i = 0; i < max; i++) {
array[i]=getFibo(i);//第i项
if (array[i]>=max) {
break;
}
}
return array;
}

// 获取第i项
private static int getFibo(int i) {
if (i == 1 || i == 2)
return 1;
else
return getFibo(i - 1) + getFibo(i - 2);}



/**
* 返回小于给定最大值max的所有素数数组
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
* @param max
* @return
*/
public int[] getPrimes(int max){
int[] array=new int[max];
for (int i = 0,j=0; i < max; i++) {
if (isPrime(i)) {
array[j]=i;
j++;
}

}
return array;
}
public static boolean isPrime(int a) {
boolean flag = true;

if (a < 2) {// 素数不小于2
return false;
} else {

for (int i = 2; i <= Math.sqrt(a); i++) {

if (a % i == 0) {// 若能被整除,则说明不是素数,返回false

flag = false;
break;// 跳出循环
}
}
}
return flag;
}

/**
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
* @param max
* @return
*/
public int[] getPerfectNumbers(int max){
int[] array=new int[max];
for (int i = 0,j=0; i < max; i++) {
if (isPrime(i)) {
array[j]=i;
j++;
}

}
return array;
}

public static boolean isPerfectNumber(int i) {
int s=0;
for(int j=1;j<i;j++){
if(i % j==0)
s=s+j;
if(s==i)
return true;
}

return false;
}


/**
* 用seperator 把数组 array给连接起来
* 例如array= [3,8,9], seperator = "-"
* 则返回值为"3-8-9"
* @param array
* @param s
* @return
*/
public String join(int[] array, String seperator){
if (array.length>0&&array!=null) {
StringBuffer stringBuffer=new StringBuffer();
stringBuffer.append(array[0]);
for (int i = 1; i < array.length; i++) {
stringBuffer.append(seperator).append(array[i]);
}
return stringBuffer.toString();
}
return null;
}


}
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package com.github.xiaozi123.coding2017.secondWork;


/**
* 这是一个用来展示登录的业务类, 其中的用户名和密码都是硬编码的。
* @author liuxin
*
*/
public class LoginAction{
private String name ;
private String password;
private String message;

public String getName() {
return name;
}

public String getPassword() {
return password;
}

public String execute(){
if("test".equals(name) && "1234".equals(password)){
this.message = "login successful";
return "success";
}
this.message = "login failed,please check your user/pwd";
return "fail";
}

public void setName(String name){
this.name = name;
}
public void setPassword(String password){
this.password = password;
}
public String getMessage(){
return this.message;
}
}

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