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Merge pull request #28 from KellyXiao/master
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week3 work
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zhijiaxinyu authored Mar 26, 2017
2 parents bcedf13 + fbf1343 commit fd411cd
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23 changes: 23 additions & 0 deletions group10/205301442/src/api/Connection.java
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package com.coderising.download.api;

import java.io.IOException;

public interface Connection {
/**
* 给定开始和结束位置, 读取数据, 返回值是字节数组
* @param startPos 开始位置, 从0开始
* @param endPos 结束位置
* @return
*/
public byte[] read(int startPos,int endPos) throws IOException;
/**
* 得到数据内容的长度
* @return
*/
public int getContentLength();

/**
* 关闭连接
*/
public void close();
}
5 changes: 5 additions & 0 deletions group10/205301442/src/api/ConnectionException.java
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package com.coderising.download.api;

public class ConnectionException extends Exception {

}
10 changes: 10 additions & 0 deletions group10/205301442/src/api/ConnectionManager.java
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package com.coderising.download.api;

public interface ConnectionManager {
/**
* 给定一个url , 打开一个连接
* @param url
* @return
*/
public Connection open(String url) throws ConnectionException;
}
6 changes: 6 additions & 0 deletions group10/205301442/src/api/DownloadListener.java
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package com.coderising.download.api;

public interface DownloadListener {
public void notifyFinished(boolean isFinish);
public boolean getIsFinished();
}
280 changes: 280 additions & 0 deletions group10/205301442/src/com/coding/week1/LinkedList1.java
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package com.coding.week1;
import java.util.List;
import java.util.ArrayList;

public class LinkedList1 {
private Node head;
private int size;
public void add(Object o){
Node node = new Node(o,null);
node(size-1).next = node;
size++;
}
public void add(int index , Object o){
if(index<0){
return;
}
Node node = new Node(o,null);
if(index==0){
head=node;
node.next = node(0);
}else{
node(index-1).next = node;
node.next = node(index+1);
}
size++;
}
public Object get(int index){
if(index<0){
return null;
}
return node(index);
}
public Object remove(int index){
if(index<0){
return null;
}
Object o =node(index).data;
node(index-1).next = node(index+1);
size--;
return o;
}

public int size(){
return -1;
}

public void addFirst(Object o){
Node n = new Node(o,null);
head = n;
if(size>0){
n.next = node(0);
}
size++;

}
public void addLast(Object o){
Node n = new Node(o,null);
if(size>0){
node(size-1).next = n;
}else{
head = n;
}
size++;

}
public Object removeFirst(){
return null;
}
public Object removeLast(){
return null;
}
public Iterator iterator(){
return new Ito();
}
public class Ito implements Iterator{
int cursor;
@Override
public boolean hasNext() {
if(cursor!=size){
return true;
}
return false;
}

@Override
public Object next() {
if(cursor>=size-1){
return null;
}
Object o=node(cursor).data;
cursor++;
return o;

}

}


private static class Node{
Object data;
Node next;
public Node(Object data,Node next){
this.data = data;
this.next = next;
}


}

/**
* 把该链表逆置
* 例如链表为 3->7->10 , 逆置后变为 10->7->3
*/
public void reverse(){
Node x = node(size-1);
head = x;
for(int i=size-2;i>=0;i--){
x.next = node(i);
x = node(i);
}
}

/**
* 删除一个单链表的前半部分
* 例如:list = 2->5->7->8 , 删除以后的值为 7->8
* 如果list = 2->5->7->8->10 ,删除以后的值为7,8,10
*/
public void removeFirstHalf(){
int newSize = size/2+size%2;
head = node(newSize-1);
size = newSize;
}

/**
* 从第i个元素开始, 删除length 个元素 , 注意i从0开始
* @param i
* @param length
*/
public void remove(int i, int length){

if(i==0){
head = node(length);
}
node(i-1).next = node(i+length);
}
/**
* 假定当前链表和listB均包含已升序排列的整数
* 从当前链表中取出那些listB所指定的元素
* 例如当前链表 = 11->101->201->301->401->501->601->701
* listB = 1->3->4->6
* 返回的结果应该是[101,301,401,601]
* @param list
*/
public int[] getElements(LinkedList list){
int[] temp = new int[size];
for(int i=0;i<size;i++){
String o= (String)node(i).data;
int j=0;
while(j<list.size()){
if(o.indexOf((String)list.get(j))>-1){
temp[0]=Integer.parseInt(o);
j++;
}
}

}
return null;
}

/**
* 已知链表中的元素以值递增有序排列,并以单链表作存储结构。
* 从当前链表中中删除在listB中出现的元素
* @param list
*/

public void subtract(LinkedList list){
int[] temp = new int[size];
int newSize = 0;
for(int i=0;i<size;i++){
String o= (String)node(i).data;
for(int j=0;j<list.size();j++){
if(list.get(j).equals(o)){
if(i+1<size){
node(i-1).next = node(i+1);
newSize--;
}else{
node(i-1).next = null;

}

}
}
}
size = newSize;
}

/**
* 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。
* 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同)
*/
public void removeDuplicateValues(){
Node now = head;
while(now.next!=null){
if(now.data.equals(now.next.data)){
if(now.next.next!=null){
now.next = now.next.next;
}
}
if(now.next!=null){
now = now.next;
}

}
}

/**
* 已知链表中的元素以值递增有序排列,并以单链表作存储结构。
* 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素)
* @param min
* @param max
*/
public void removeRange(int min, int max){
Node n = head;
List<Node> lists = new ArrayList<Node>();
while(true){
if((int)n.data>min&&(int)n.data<max){
return;
}
lists.add(n);
if(n.next==null){
break;
}
n = n.next;
}
head = lists.get(0);
Node node = head;
for(int i=1;i<lists.size();i++){
node.next = lists.get(i);

node = node.next;
}
}

/**
* 假设当前链表和参数list指定的链表均以元素依值递增有序排列(同一表中的元素值各不相同)
* 现要求生成新链表C,其元素为当前链表和list中元素的交集,且表C中的元素有依值递增有序排列
* @param list
*/
public LinkedList1 intersection( LinkedList1 list){
LinkedList1 l = new LinkedList1();
Node n1 = head;
Node n2 = (Node) list.get(0);;
while(n1!=null){
while(n2!=null){
if(n1.data.equals(n2.data)){
l.add(n1);
}
n2 = n2.next;
}
n1 = n1.next;
}
return l;
}
public Node node(int index){
if(index<0){
return null;
}
if(index==0){
return head;
}
Node x =head;
for(int i=0;i<index;i++ ){
x = x.next;
}

return x;
}
}
28 changes: 28 additions & 0 deletions group10/205301442/src/download/DownloadThread.java
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package com.coderising.download;

import java.io.IOException;

import com.coderising.download.api.Connection;

public class DownloadThread extends Thread{

Connection conn;
int startPos;
int endPos;
byte[] reads;
public DownloadThread( Connection conn, int startPos, int endPos){

this.conn = conn;
this.startPos = startPos;
this.endPos = endPos;
}
public void run(){
try {
reads=conn.read(startPos, endPos);

} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
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