README_EN.md

492. Construct the Rectangle

中文文档

Description

A web developer needs to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

Return an array [L, W] where L and W are the length and width of the web page you designed in sequence.

 

Example 1:

Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Example 2:

Input: area = 37
Output: [37,1]

Example 3:

Input: area = 122122
Output: [427,286]

 

Constraints:

• 1 <= area <= 107

Solutions

Python3

class Solution:
    def constructRectangle(self, area: int) -> List[int]:
        sr = int(math.sqrt(area))
        l = w = sr
        while l <= area and w >= 1:
            s = l * w
            if s == area:
                break
            if s > area:
                w -= 1
            else:
                l += 1
        return [l, w]

Java

class Solution {
    public int[] constructRectangle(int area) {
        int sr = (int) Math.sqrt(area);
        int l = sr, w = sr;
        while (l <= area && w >= 1) {
            int s = l * w;
            if (s == area) break;
            if (s > area) --w;
            else ++l;
        }
        return new int[]{l, w};
    }
}

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