log_encode.sf

#!/usr/bin/ruby

# Author: Trizen
# Date: 02 April 2022
# https://github.com/trizen

# Encode data, using logarithms of integers.

# Example:
#   Let's say we want to encode the bytes "abc" == [97, 98, 99]
#   We try to find an integer n such that log(n) contains '097098099' after the decimal point.
#   One such integer is 1453293358, which gives log(1453293358) = 21.097098099...

# Usage:
#   sidef script.sf [input_file]

# The script generates a valid Sidef script as output, such that, when executed, it will produce the input data.

define (
    PERL_CODE = false        # true to generate Perl code
    SLICE_SIZE = 1           # how many bytes to encode into an integer
)

func log_encode(bytes) {
    var v = bytes.map { '%03d' % _ }.join
    for n in (10 .. 99) {
        var t = Num("#{n}.#{v}").exp.round
        if (t.log.to_s.substr(3).begins_with(v)) {
            return t
        }
    }
    return nil
}

var text = File(ARGV[0] \\ __FILE__).read

var values = []

text.bytes.each_slice(SLICE_SIZE, {|*slice|

    while (slice.len != SLICE_SIZE) {
        slice += ' '.ord
    }

    values << log_encode(slice)
})

if (PERL_CODE) {
    print %Q'print pack("C#{SLICE_SIZE}", unpack("x3(a3)#{SLICE_SIZE}", log)) for qw('
    print values.join(' ')
    say ')'
}
else {
    print 'STDOUT.binmode(":raw");%n['
    print values.join(' ')
    say %Q'].each { pack("C#{SLICE_SIZE}", unpack("x3(a3)#{SLICE_SIZE}", .log)).print }'
}