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sort doesn't infer in simple case #338

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wclr opened this issue Nov 23, 2017 · 1 comment

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question upstream

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wclr commented Nov 23, 2017

I believe sort should always return type of passed array:
Be able to check typings in inner comparator

    type A = { x: number }    
    const list: A[] = [{ x: 1 }, {x: 2}]
    const sorted = R.sort(R.ascend(R.prop('y')), list)

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ikatyang commented Nov 24, 2017

Unfortunately this is a TS limitation, see microsoft/TypeScript#16914 for more info.

ikatyang added question upstream labels

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