From 09c702a128ac6b958f3c13c58349aaf07587d238 Mon Sep 17 00:00:00 2001 From: David Chen Date: Sun, 17 May 2020 23:30:00 +0800 Subject: [PATCH] =?UTF-8?q?Update=202020-05-17-=E7=9F=A9=E9=98=B5=E6=B1=82?= =?UTF-8?q?=E5=AF=BC=E7=9A=84Trace-Trick.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- ...1\230\265\346\261\202\345\257\274\347\232\204Trace-Trick.md" | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git "a/_posts/2020-05-17-\347\237\251\351\230\265\346\261\202\345\257\274\347\232\204Trace-Trick.md" "b/_posts/2020-05-17-\347\237\251\351\230\265\346\261\202\345\257\274\347\232\204Trace-Trick.md" index 8d18cdb385f..eda0121cdfe 100644 --- "a/_posts/2020-05-17-\347\237\251\351\230\265\346\261\202\345\257\274\347\232\204Trace-Trick.md" +++ "b/_posts/2020-05-17-\347\237\251\351\230\265\346\261\202\345\257\274\347\232\204Trace-Trick.md" @@ -90,7 +90,7 @@ $$ - $$tr(X^\top) = tr(X)$$ 转置trace一样 - $$tr(A+B) = tr(A)+tr(B)$$ 线性拆分 - $$tr(A^\top B) = tr(B^\top A)$$ 满足交换律 -- $$tr(A^\top (B \circ C)) = tr((A \circ B)^\top C)$$，这里三个矩阵$$A,B,C$$的大小相同。 +- $$tr(A^\top (B \circ C)) = tr((A \circ B)^\top C)$$，这里三个矩阵$$A,B,C$$的大小相同。证明略。 # 举例