Task description
A string S consisting of N characters is called properly nested if:
- S is empty;
- S has the form "(U)" where U is a properly nested string;
- S has the form "VW" where V and W are properly nested strings.
For example, string "(()(())())" is properly nested but string "())" isn't.
Write a function:
function solution(S);
that, given a string S consisting of N characters, returns 1 if string S is properly nested and 0 otherwise.
For example, given S = "(()(())())", the function should return 1 and given S = "())", the function should return 0, as explained above.
Assume that:
- N is an integer within the range [0..1,000,000];
- string S consists only of the characters "(" and/or ")".
Complexity:
- expected worst-case time complexity is O(N);
- expected worst-case space complexity is O(1) (not counting the storage required for input arguments).
function solution(S) {
let counter = 0;
for (var i = 0; i < S.length; i++) {
switch(S[i]) {
case "(":
counter++;
break;
case ")":
counter--;
break;
}
if (counter < 0) return 0
}
return counter === 0 ? 1 : 0
}