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1158154002
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test02
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sheng committed Mar 5, 2017
1 parent 82af472 commit 5bf4816
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241 changes: 241 additions & 0 deletions group17/1158154002/src/test02/array/ArrayUtil.java
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package test02.array;

import java.util.ArrayList;
import java.util.Arrays;

import com.sun.javafx.image.impl.IntArgb;

public class ArrayUtil {

public static void main(String[] args) {
// int[] arr={7, 9, 30, 3, 4};
// reverseArray(arr);

// int[] oldArr={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5};
// removeZero(oldArr);

// int[] a1={3, 5, 7,8};
// int[] a2={4, 5, 6,7};
// merge(a1,a2);

// int[] a1={3, 5, 7,8};
// grow(a1, 3);

// fibonacci(15);

// getPrimes(23);

// getPerfectNumbers(4000);

int[] a={1,2,3,4};
join(a, "-");
}

/**
* 给定一个整形数组a , 对该数组的值进行置换
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
* @param origin
* @return
*/
public static void reverseArray(int[] origin){
int[] newArr=new int[origin.length];
int j=0;
for (int i = origin.length-1; i >=0; i--) {
newArr[j++]=origin[i];
}
System.out.println(Arrays.toString(newArr));
}

/**
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
* {1,3,4,5,6,6,5,4,7,6,7,5}
* @param oldArray
* @return
*/

public static int[] removeZero(int[] oldArray){
ArrayList<Integer> list=new ArrayList<>();
for (int i = 0; i < oldArray.length; i++) {
if (oldArray[i]!=0) {
list.add(oldArray[i]);
}
}

int[] newArr=new int[list.size()];
int j=0;
for (int i : list) {
newArr[j++]=i;
}
System.out.println(Arrays.toString(newArr));
return newArr;
}

/**
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
* @param array1
* @param array2
* @return
*/

public static int[] merge(int[] array1, int[] array2){
ArrayList<Integer> list=new ArrayList<>();
for (Integer arr1 : array1) {
list.add(arr1);
}

for (Integer arr2 : array2) {
if (!list.contains(arr2)) {
list.add(arr2);
}
}

int[] newArr=new int[list.size()];
int i=0;
for (int one : list) {
newArr[i++]=one;
}

for (int j = 0; j < newArr.length-1; j++) {
for (int k = 0; k < newArr.length-1-j; k++) {

if (newArr[k]>newArr[k+1]) {
int temp=newArr[k];
newArr[k]=newArr[k+1];
newArr[k+1]=temp;
}
}
}
System.out.println(Arrays.toString(newArr));
return newArr;
}
/**
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
* 注意,老数组的元素在新数组中需要保持
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
* [2,3,6,0,0,0]
* @param oldArray
* @param size
* @return
*/
public static int[] grow(int [] oldArray, int size){
int[] newArr=new int[oldArray.length+size];
System.arraycopy(oldArray, 0, newArr, 0, oldArray.length);
System.out.println(Arrays.toString(newArr));
return newArr;
}

/**
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
* max = 1, 则返回空数组 []
* @param max
* @return
*/
public static int[] fibonacci(int max){
if (max>1) {
ArrayList<Integer> list=new ArrayList<>();
list.add(1);
list.add(1);
while (list.get(list.size()-1)<max) {
if ((list.get(list.size()-1)+list.get(list.size()-2))<max) {
list.add(list.get(list.size()-1)+list.get(list.size()-2));
}else {
break;
}
}
int[] newArr=new int[list.size()];
int i=0;
for (int item : list) {
newArr[i++]=item;
}
System.out.println(Arrays.toString(newArr));
return newArr;
} else {
return null;
}
}

/**
* 返回小于给定最大值max的所有素数数组
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
* @param max
* @return
*/
public static int[] getPrimes(int max) {
ArrayList<Integer> list = new ArrayList<>();

for (int i = 2; i < max; i++) {
int j = 2;
while (j < i) {
// System.out.println("i:"+i+",j:"+j+",i%j:"+(i%j));
if (i%j==0) {
break;
}
j++;
}
if (j==i) {
list.add(i);
}
}

int[] newArr = new int[list.size()];
int i = 0;
for (int item : list) {
newArr[i++] = item;
}
System.out.println(Arrays.toString(newArr));

return newArr;
}

/**
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
* @param max
* @return
*/
public static int[] getPerfectNumbers(int max){
ArrayList<Integer> list = new ArrayList<>();
for (int i = 1; i < max; i++) {
int j = 1;
int sum=0;
while (j < i) {
// System.out.println("i:"+i+",j:"+j+",i%j:"+(i%j));
if (i%j==0) {
sum=sum+j;
}
j++;
}

if (sum==i) {
list.add(i);
}
}

int[] newArr = new int[list.size()];
int i = 0;
for (int item : list) {
newArr[i++] = item;
}
System.out.println(Arrays.toString(newArr));

return newArr;
}

/**
* 用seperator 把数组 array给连接起来
* 例如array= [3,8,9], seperator = "-"
* 则返回值为"3-8-9"
* @param array
* @param s
* @return
*/
public static String join(int[] array, String seperator){
String result=Arrays.toString(array).replace(" ", "").replace("[", "").replace("]", "").replace(",", seperator);
System.out.println(result);
return result;
}
}
22 changes: 22 additions & 0 deletions group17/1158154002/src/test02/litestruts/Action.java
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package test02.litestruts;

import java.util.HashMap;

public class Action {
String className;
HashMap<String, String> resultJspMap;

public String getClassName() {
return className;
}
public void setClassName(String className) {
this.className = className;
}
public HashMap<String, String> getResultJspMap() {
return resultJspMap;
}
public void setResultJspMap(HashMap<String, String> resultJspMap) {
this.resultJspMap = resultJspMap;
}

}
39 changes: 39 additions & 0 deletions group17/1158154002/src/test02/litestruts/LoginAction.java
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package test02.litestruts;

/**
* 这是一个用来展示登录的业务类, 其中的用户名和密码都是硬编码的。
* @author liuxin
*
*/
public class LoginAction{
private String name ;
private String password;
private String message;

public String getName() {
return name;
}

public String getPassword() {
return password;
}

public String execute(){
if("test".equals(name) && "1234".equals(password)){
this.message = "login successful";
return "success";
}
this.message = "login failed,please check your user/pwd";
return "fail";
}

public void setName(String name){
this.name = name;
}
public void setPassword(String password){
this.password = password;
}
public String getMessage(){
return this.message;
}
}
60 changes: 60 additions & 0 deletions group17/1158154002/src/test02/litestruts/Struts.java
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package test02.litestruts;

import java.lang.reflect.Method;
import java.util.HashMap;
import java.util.Map;

import test02.litestruts.sax.SAXParserDemo;
import test02.litestruts.util.StringUtil;

public class Struts {

public static View runAction(String actionName, Map<String,String> parameters){

/*
0. 读取配置文件struts.xml
1. 根据actionName找到相对应的class , 例如LoginAction, 通过反射实例化(创建对象)
据parameters中的数据,调用对象的setter方法, 例如parameters中的数据是
("name"="test" , "password"="1234") ,
那就应该调用 setName和setPassword方法
2. 通过反射调用对象的exectue 方法, 并获得返回值,例如"success"
3. 通过反射找到对象的所有getter方法(例如 getMessage),
通过反射来调用, 把值和属性形成一个HashMap , 例如 {"message": "登录成功"} ,
放到View对象的parameters
4. 根据struts.xml中的 <result> 配置,以及execute的返回值, 确定哪一个jsp,
放到View对象的jsp字段中。
*/

Action action = SAXParserDemo.run();
View view=new View();
try {
Class<?> clazz = Class.forName(action.getClassName());
Object obj = clazz.newInstance();
for (String element : parameters.keySet()) {
Method method = clazz.getMethod("set" + StringUtil.captureName(element), String.class);
method.invoke(obj, parameters.get(element));
}
Method exectue = clazz.getMethod("execute", null);
String result = (String) exectue.invoke(obj, null);
view.setJsp(action.getResultJspMap().get(result));

Method getMsg = clazz.getMethod("getMessage", null);
String msg=(String) getMsg.invoke(obj, null);
Map map=new HashMap<>();
map.put("message", msg);
System.out.println(map);
view.setParameters(map);

} catch (Exception e) {
e.printStackTrace();
}
return view;
}

}
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