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Copy path144.binary-tree-preorder-traversal.java
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144.binary-tree-preorder-traversal.java
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/*
* @lc app=leetcode id=144 lang=java
*
* [144] Binary Tree Preorder Traversal
*
* https://leetcode.com/problems/binary-tree-preorder-traversal/description/
*
* algorithms
* Medium (54.38%)
* Likes: 1291
* Dislikes: 54
* Total Accepted: 459.1K
* Total Submissions: 842.4K
* Testcase Example: '[1,null,2,3]'
*
* Given a binary tree, return the preorder traversal of its nodes' values.
*
* Example:
*
*
* Input: [1,null,2,3]
* 1
* \
* 2
* /
* 3
*
* Output: [1,2,3]
*
*
* Follow up: Recursive solution is trivial, could you do it iteratively?
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> result = new ArrayList<>();
if (root == null) return result;
Stack<TreeNode> stack = new Stack<>();
stack.push(root);
while (!stack.isEmpty()) {
TreeNode node = stack.pop();
result.add(node.val);
if (node.right != null) stack.push(node.right);
if (node.left != null) stack.push(node.left);
}
return result;
}
}
// @lc code=end