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Merge pull request #26 from maishihang/master
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2week homework
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guodongym authored Mar 6, 2017
2 parents 88d610b + 6304409 commit 1c77056
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42 changes: 42 additions & 0 deletions group12/446031103/src/com/coderising/action/LoginAction.java
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package com.coderising.action;

/**
* 这是一个用来展示登录的业务类, 其中的用户名和密码都是硬编码的。
* @author liuxin
*
*/
public class LoginAction{
private String name ;
private String password;
private String message;

public String getName() {
return name;
}

public String getPassword() {
return password;
}

public String execute(){
if("test".equals(name) && "1234".equals(password)){
this.message = "login successful";
return "success";
}
this.message = "login failed,please check your user/pwd";
return "fail";
}

public void setName(String name){
this.name = name;
}
public void setPassword(String password){
this.password = password;
}
public String getMessage(){
return this.message;
}
public void setMessage(String message){
this.message = message;
}
}
202 changes: 202 additions & 0 deletions group12/446031103/src/com/coderising/array/ArrayUtil.java
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package com.coderising.array;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class ArrayUtil {

/**
* 给定一个整形数组a , 对该数组的值进行置换
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
* @param origin
* @return
*/
public void reverseArray(int[] origin){
int end = origin.length-1;
int temp ;
for (int i = 0; i < end; i++,end--) {
temp=origin[i];
origin[i]=origin[end];
origin[end] = temp;
}
}

/**
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
* {1,3,4,5,6,6,5,4,7,6,7,5}
* @param oldArray
* @return
*/

public int[] removeZero(int[] oldArray){
int zeroCnt = 0;
for (int i : oldArray) {
if(0==i){
zeroCnt++;
}

}
int size = 0;
int [] result = new int[oldArray.length-zeroCnt];
for (int i : oldArray) {
if(0!=i){
result[size]=i;
size++;
}

}
return result;
}

/**
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
* @param array1
* @param array2
* @return
*/

public int[] merge(int[] array1, int[] array2){
//合拼数组,缺排序,缺去重
int [] temp = new int[array1.length+array2.length];
System.arraycopy(array1, 0, temp, 0, array1.length);
System.arraycopy(array2, 0, temp, array1.length, array2.length);
List<Integer> resultList= new ArrayList<Integer>();
for (int i : temp) {
if(!resultList.contains(i))
resultList.add(i);
}//已去重数组,缺排序
int [] result = new int[resultList.size()];
for (int i = 0; i < resultList.size(); i++) {
result[i] = resultList.get(i);
}
//冒泡排序
for (int i = 0; i < result.length-1; i++) {
for (int j = 0; j < result.length-i-1; j++) {
if(result[j]>result[j+1]){
int tempInt = result[j];
result[j] =result[j+1];
result[j+1] = tempInt;
}
}

}
return result;
}
/**
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
* 注意,老数组的元素在新数组中需要保持
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
* [2,3,6,0,0,0]
* @param oldArray
* @param size
* @return
*/
public int[] grow(int [] oldArray, int size){
return Arrays.copyOf(oldArray, oldArray.length+size);
}

/**
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
* max = 1, 则返回空数组 []
* @param max
* @return
*/
public int[] fibonacci(int max){
int first =0;
int second = 1;
List<Integer> resultList= new ArrayList<Integer>();
if(max!=second)
add(first,second,max,resultList);
int [] result = new int[resultList.size()];
for (int i = 0; i < resultList.size(); i++) {
result[i] = resultList.get(i);
}
return result;
}

/**
* 返回小于给定最大值max的所有素数数组
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
* @param max
* @return
*/
public int[] getPrimes(int max){
List<Integer> resultList= new ArrayList<Integer>();
for (int i = 2; i < max; i++) {
boolean isAdd = true;
for (int j = 2; j < i; j++) {
if(0==i%j){
isAdd = false;
break;
}
}
if(isAdd)
resultList.add(i);
}
int [] result = new int[resultList.size()];
for (int i = 0; i < resultList.size(); i++) {
result[i] = resultList.get(i);
}
return result;
}

/**
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
* @param max
* @return
*/
public int[] getPerfectNumbers(int max){
List<Integer> resultList= new ArrayList<Integer>();
for (int i = 1; i < max; i++) {
int temp = 0;
for (int j = 1; j < i; j++) {
if(0==i%j){
temp+=j;
}
}
if(i==temp)
resultList.add(i);
}
int [] result = new int[resultList.size()];
for (int i = 0; i < resultList.size(); i++) {
result[i] = resultList.get(i);
}
return result;
}

/**
* 用seperator 把数组 array给连接起来
* 例如array= [3,8,9], seperator = "-"
* 则返回值为"3-8-9"
* @param array
* @param s
* @return
*/
public String join(int[] array, String seperator){
return Arrays.toString(array).replace("[", "").replace("]", "").replace(", ", seperator);
}

/**
*
* @param number1
* @param number2
* @param max
* @param resultList
* @return
*/
public List<Integer> add(int number1,int number2,int max,List<Integer> resultList){
if(number2<max){
resultList.add(number2);
return add(number2,number1+number2,max,resultList);
}else{
return resultList;
}
};

}
107 changes: 107 additions & 0 deletions group12/446031103/src/com/coderising/array/ArrayUtilTest.java
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package com.coderising.array;

import static org.junit.Assert.*;

import java.util.Arrays;

import org.junit.After;
import org.junit.Before;
import org.junit.Test;

import junit.framework.Assert;

@SuppressWarnings({ "deprecation", "unused" })
public class ArrayUtilTest {
ArrayUtil au = new ArrayUtil();
@Before
public void setUp() throws Exception {
}

@After
public void tearDown() throws Exception {
}

@Test
public void testReverseArray() {
int [] origin = {4,7, 9 , 30, 3};
au.reverseArray(origin);
Assert.assertEquals(3, origin[0]);
Assert.assertEquals(30, origin[1]);
Assert.assertEquals(9, origin[2]);
Assert.assertEquals(7, origin[3]);
Assert.assertEquals(4, origin[4]);
}

@Test
public void testRemoveZero() {
int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5};
int [] result=au.removeZero(oldArr);
Assert.assertEquals(false, Arrays.asList(result).contains(0));
}

@Test
public void testMerge() {
int [] array1 = {3,5,7,8};
int [] array2 = {4,5,6,7};
int [] array3 = au.merge(array1, array2);
Assert.assertEquals(3, array3[0]);
Assert.assertEquals(4, array3[1]);
Assert.assertEquals(5, array3[2]);
Assert.assertEquals(6, array3[3]);
Assert.assertEquals(7, array3[4]);
Assert.assertEquals(8, array3[5]);
}

@Test
public void testGrow() {
int []oldArray = {2,3,6};
int [] result=au.grow(oldArray, 3);
Assert.assertEquals(2, result[0]);
Assert.assertEquals(3, result[1]);
Assert.assertEquals(6, result[2]);
Assert.assertEquals(0, result[3]);
Assert.assertEquals(0, result[4]);
Assert.assertEquals(0, result[5]);
}

@Test
public void testFibonacci() {
int [] result= au.fibonacci(22);
Assert.assertEquals(1, result[0]);
Assert.assertEquals(1, result[1]);
Assert.assertEquals(2, result[2]);
Assert.assertEquals(3, result[3]);
Assert.assertEquals(5, result[4]);
Assert.assertEquals(8, result[5]);
Assert.assertEquals(13, result[6]);
Assert.assertEquals(21, result[7]);
}

@Test
public void testGetPrimes() {
int [] result=au.getPrimes(23);
Assert.assertEquals(2, result[0]);
Assert.assertEquals(3, result[1]);
Assert.assertEquals(5, result[2]);
Assert.assertEquals(7, result[3]);
Assert.assertEquals(11, result[4]);
Assert.assertEquals(13, result[5]);
Assert.assertEquals(17, result[6]);
Assert.assertEquals(19, result[7]);
}

@Test
public void testGetPerfectNumbers() {
int [] result=au.getPerfectNumbers(100);
Assert.assertEquals(6, result[0]);
Assert.assertEquals(28, result[1]);
}

@Test
public void testJoin() {
int [] array = {3,8,9};
String result=au.join(array, "-");
Assert.assertEquals("3-8-9",result);
}

}
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