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group08/1425809544/02-26/com/xuyangyang/util_1/ArrayUtil.java
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package com.util_1; | ||
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import java.util.*; | ||
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public class ArrayUtil { | ||
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/** | ||
* 给定一个整形数组a , 对该数组的值进行置换 | ||
* 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] | ||
* 如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] | ||
* | ||
* @param origin | ||
* @return | ||
*/ | ||
public void reverseArray(int[] origin) { | ||
int[] oldArr = origin; | ||
int newLength = oldArr.length; | ||
int[] newArr = new int[newLength]; | ||
for (int i = 0; i < newLength; i++) { | ||
newArr[newLength - i - 1] = oldArr[i]; | ||
} | ||
for (int s : newArr) { | ||
System.out.println(s); | ||
} | ||
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} | ||
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/** | ||
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} | ||
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: | ||
* {1,3,4,5,6,6,5,4,7,6,7,5} | ||
* | ||
* @param oldArray | ||
* @return | ||
*/ | ||
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public int[] removeZero(int[] oldArray) { | ||
int[] oldArr = oldArray; | ||
int oldLength = oldArr.length; | ||
int[] newArr = new int[oldLength]; | ||
int index = 0; | ||
int zeroCount = 0; | ||
for (int i = 0; i < oldLength; i++) { | ||
if (oldArr[i] == 0) { | ||
zeroCount++; | ||
} else { | ||
newArr[index++] = oldArr[i]; | ||
} | ||
} | ||
int[] newArrs = Arrays.copyOf(newArr, index); | ||
return newArrs; | ||
} | ||
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/** | ||
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 | ||
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 | ||
* | ||
* @param array1 | ||
* @param array2 | ||
* @return | ||
*/ | ||
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public int[] merge(int[] array1, int[] array2) { | ||
int newLength = array1.length + array2.length; | ||
int[] newArr = new int[newLength]; | ||
int index = 0; | ||
for (int i = 0; i < array1.length; i++) { | ||
newArr[index++] = array1[i]; | ||
} | ||
for (int i = 0; i < array2.length; i++) { | ||
newArr[index++] = array2[i]; | ||
} | ||
//冒泡排序 | ||
for (int i = 0; i < newArr.length; i++) { | ||
for (int j = i + 1; j < newArr.length; j++) { | ||
if (newArr[i] > newArr[j]) { | ||
int temp = newArr[i]; | ||
newArr[i] = newArr[j]; | ||
newArr[j] = temp; | ||
} | ||
} | ||
} | ||
//数组去重 | ||
boolean[] b = new boolean[newArr.length]; | ||
int counts = newArr.length; | ||
for (int i = 0; i < newArr.length; i++) { | ||
for (int j = i + 1; j < newArr.length; j++) { | ||
if (newArr[i] == newArr[j] && b[i] == false) { | ||
b[j] = true; | ||
counts--; | ||
} | ||
} | ||
} | ||
int[] result = new int[counts]; | ||
int j = 0; | ||
for (int i = 0; i < newArr.length; i++) { | ||
if (b[i] == false) { | ||
result[j] = newArr[i]; | ||
j++; | ||
} | ||
} | ||
return result; | ||
} | ||
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/** | ||
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size | ||
* 注意,老数组的元素在新数组中需要保持 | ||
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 | ||
* [2,3,6,0,0,0] | ||
* | ||
* @param oldArray | ||
* @param size | ||
* @return | ||
*/ | ||
public int[] grow(int[] oldArray, int size) { | ||
int oldLength = oldArray.length; | ||
int newLength = oldLength + size; | ||
int[] result = Arrays.copyOf(oldArray, newLength); | ||
return result; | ||
} | ||
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/** | ||
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 | ||
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13] | ||
* max = 1, 则返回空数组 [] | ||
* | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] fibonacci(int max) { | ||
int a = 1, b = 1, c = 2; | ||
int[] arr = new int[max + 1]; | ||
int i = 2; | ||
if (max == 1) { | ||
return Arrays.copyOf(arr, 0); | ||
} else if (max <= 0) { | ||
throw new IllegalArgumentException("不能输入<=0的参数:" + max); | ||
} else { | ||
arr[0] = 1; | ||
arr[1] = 1; | ||
do { | ||
c = a + b; | ||
a = b; | ||
b = c; | ||
arr[i++] = c; | ||
} while (c < max); | ||
} | ||
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if (arr[i - 1] >= max) { | ||
return Arrays.copyOf(arr, i - 1); | ||
} | ||
return Arrays.copyOf(arr, i); | ||
} | ||
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/** | ||
* 返回小于给定最大值max的所有素数数组 | ||
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] | ||
* | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] getPrimes(int max) { | ||
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class IsPrime { | ||
// 判断某整数是否为素数 | ||
public boolean isPrimes(int n) { | ||
if (n < 2) { | ||
return false; | ||
} | ||
for (int i = 2; i * i <= n; i++) { | ||
if (n % i == 0) { | ||
return false; | ||
} | ||
} | ||
return true; | ||
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} | ||
} | ||
List list = new ArrayList(); | ||
IsPrime isPrime = new IsPrime(); | ||
for (int i = 2; i < max; i++) { | ||
if (isPrime.isPrimes(i)) { | ||
list.add(i); | ||
} | ||
} | ||
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int[] arr = new int[list.size()]; | ||
for (int i = 0; i < list.size(); i++) { | ||
arr[i] = (int) list.get(i); | ||
} | ||
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return arr; | ||
} | ||
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/** | ||
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 | ||
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 | ||
* | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] getPerfectNumbers(int max) { | ||
//保存每组的分解因子 | ||
List list = new ArrayList(); | ||
List pm = new ArrayList(); | ||
int sum = 0; | ||
//除数 | ||
for (int i = 2; i < max; i++) { | ||
//被除数 | ||
sum=0; | ||
for (int j = 1; j < i / 2 + 1; j++) { | ||
if (i % j == 0) { | ||
list.add(j); | ||
sum += j; | ||
} | ||
} | ||
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if (sum == i) { | ||
pm.add(i); | ||
} | ||
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list.clear(); | ||
} | ||
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int[] pmaArr = new int[pm.size()]; | ||
for (int i = 0; i < pm.size(); i++) { | ||
pmaArr[i] = (int) pm.get(i); | ||
} | ||
return pmaArr; | ||
} | ||
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/** | ||
* 用seperator 把数组 array给连接起来 | ||
* 例如array= [3,8,9], seperator = "-" | ||
* 则返回值为"3-8-9" | ||
* | ||
* @param array | ||
* @param | ||
* @return | ||
*/ | ||
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public String join(int[] array, String seperator) { | ||
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String s = new String(); | ||
for (int i = 0; i < array.length; i++) { | ||
if (i < array.length - 1) { | ||
s += array[i] + seperator; | ||
} else { | ||
s += array[i]; | ||
} | ||
} | ||
return s; | ||
} | ||
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} |
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group08/1425809544/02-26/com/xuyangyang/util_1/ArrayUtilTest.java
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package com.util_1; | ||
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import org.junit.After; | ||
import org.junit.Before; | ||
import org.junit.Test; | ||
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import static org.junit.Assert.*; | ||
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/** | ||
* Created by 14258 on 2017/2/28. | ||
*/ | ||
public class ArrayUtilTest { | ||
ArrayUtil arrayUtil = new ArrayUtil(); | ||
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@Before | ||
public void setUp() throws Exception { | ||
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} | ||
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@After | ||
public void tearDown() throws Exception { | ||
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} | ||
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@Test | ||
public void testReverseArray() throws Exception { | ||
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int[] testArr = {7, 9, 30, 3}; | ||
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arrayUtil.reverseArray(testArr); | ||
} | ||
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@Test | ||
public void testRemoveZero() throws Exception { | ||
int oldArr[] = {1, 3, 4, 5, 0, 0, 6, 6, 0, 5, 4, 7, 6, 7, 0, 5}; | ||
int[] newArr = arrayUtil.removeZero(oldArr); | ||
for (int s : newArr) { | ||
System.out.println(s); | ||
} | ||
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} | ||
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@Test | ||
public void testMerge() throws Exception { | ||
int[] a1 = {3, 5, 7}; | ||
int[] a2 = {4, 5, 6, 7}; | ||
int[] newArr = arrayUtil.merge(a1, a2); | ||
for (int s : newArr) { | ||
System.out.println(s); | ||
} | ||
} | ||
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@Test | ||
public void testGrow() throws Exception { | ||
int[] oldArray = {2, 3, 6}; | ||
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int[] newArr = arrayUtil.grow(oldArray, 3); | ||
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for (int s : newArr) { | ||
System.out.println(s); | ||
} | ||
} | ||
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@Test | ||
public void testFibonacci() throws Exception { | ||
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int[] newArr = arrayUtil.fibonacci(16); | ||
System.out.print("["); | ||
for (int i : newArr) { | ||
System.out.print(i+","); | ||
} | ||
System.out.print("]"); | ||
} | ||
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@Test | ||
public void testGetPrimes() throws Exception { | ||
int[] prime = arrayUtil.getPrimes(23); | ||
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for (int i :prime){ | ||
System.out.print(i+" "); | ||
} | ||
} | ||
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@Test | ||
public void testGetPerfectNumbers() throws Exception { | ||
int[] prime = arrayUtil.getPerfectNumbers(10000); | ||
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for (int i :prime){ | ||
System.out.print(i+" "); | ||
} | ||
} | ||
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@Test | ||
public void testJoin() throws Exception { | ||
int[] array = {3, 8, 9}; | ||
String s = arrayUtil.join(array, "-"); | ||
System.out.println(s); | ||
} | ||
} |
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