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Ok #20

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Mar 5, 2017
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Ok #20

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7 changes: 7 additions & 0 deletions group10/3314793852/second/.classpath
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<?xml version="1.0" encoding="UTF-8"?>
<classpath>
<classpathentry kind="src" path="src"/>
<classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/JavaSE-1.8"/>
<classpathentry kind="con" path="org.eclipse.jdt.junit.JUNIT_CONTAINER/4"/>
<classpathentry kind="output" path="bin"/>
</classpath>
1 change: 1 addition & 0 deletions group10/3314793852/second/.gitignore
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/bin/
17 changes: 17 additions & 0 deletions group10/3314793852/second/.project
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<?xml version="1.0" encoding="UTF-8"?>
<projectDescription>
<name>2017Learning</name>
<comment></comment>
<projects>
</projects>
<buildSpec>
<buildCommand>
<name>org.eclipse.jdt.core.javabuilder</name>
<arguments>
</arguments>
</buildCommand>
</buildSpec>
<natures>
<nature>org.eclipse.jdt.core.javanature</nature>
</natures>
</projectDescription>
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eclipse.preferences.version=1
encoding//src/com/coderising/litestruts=UTF-8
encoding//src/com/coderising/litestruts/Struts.java=UTF-8
encoding/<project>=UTF-8
11 changes: 11 additions & 0 deletions group10/3314793852/second/.settings/org.eclipse.jdt.core.prefs
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eclipse.preferences.version=1
org.eclipse.jdt.core.compiler.codegen.inlineJsrBytecode=enabled
org.eclipse.jdt.core.compiler.codegen.targetPlatform=1.8
org.eclipse.jdt.core.compiler.codegen.unusedLocal=preserve
org.eclipse.jdt.core.compiler.compliance=1.8
org.eclipse.jdt.core.compiler.debug.lineNumber=generate
org.eclipse.jdt.core.compiler.debug.localVariable=generate
org.eclipse.jdt.core.compiler.debug.sourceFile=generate
org.eclipse.jdt.core.compiler.problem.assertIdentifier=error
org.eclipse.jdt.core.compiler.problem.enumIdentifier=error
org.eclipse.jdt.core.compiler.source=1.8
236 changes: 236 additions & 0 deletions group10/3314793852/second/src/com/coderising/array/ArrayUtil.java
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package com.coderising.array;

import java.util.Arrays;

public class ArrayUtil {

/**
* 给定一个整形数组a , 对该数组的值进行置换
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
* @param origin
* @return
*/
public void reverseArray(int[] origin){
int size=origin.length-1;
int[] arr=new int[origin.length];
for(int i=0;i<origin.length;i++){
arr[size]=origin[i];
size--;
}

//输出结果
for(int i=0;i<arr.length;i++){
System.out.println(arr[i]);
}
}

/**
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
* {1,3,4,5,6,6,5,4,7,6,7,5}
* @param oldArray
* @return
*/

public int[] removeZero(int[] oldArray){

int[] arr=new int[oldArray.length];
int size=0;
for(int i=0;i<oldArray.length;i++){
if(oldArray[i]!=0){
arr[size]=oldArray[i];
size++;
}
}

int[] newArr=new int[size];//将不为零的数赋值给一个新的数组。
for(int i=0;i<size;i++){
newArr[i]=arr[i];
}
return newArr;
}

/**
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
* @param array1
* @param array2
* @return
*/

public int[] merge(int[] array1, int[] array2){

int strLen1=array1.length; //保存第一个数组长度
int strLen2=array2.length; //保存第二个数组长度
array1= Arrays.copyOf(array1,strLen1+ strLen2); //扩容
System.arraycopy(array2, 0, array1, strLen1,strLen2 ); //将第二个数组与第一个数组合并
System.out.println(Arrays.toString(array1)); //输出数组

//冒泡排序,并除去重复项。
for(int i=0;i<array1.length;i++){
for(int j=i+1;j<array1.length;j++){
if(array1[i]>array1[j]&&array1[i]!=0&&array1[j]!=0){
int temp;
temp=array1[i];
array1[i]=array1[j];
array1[j]=temp;
}
if(array1[i]==array1[j]&&array1[i]!=0&&array1[j]!=0){
array1[j]=0;
}
}
}

System.out.println(Arrays.toString(array1));

int[] array3=removeZero(array1); //除零操作。
return array3;
}
/**
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
* 注意,老数组的元素在新数组中需要保持
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
* [2,3,6,0,0,0]
* @param oldArray
* @param size
* @return
*/
public int[] grow(int [] oldArray, int size){
int[] newArr=new int[oldArray.length+size];
for(int i=0;i<oldArray.length;i++){
newArr[i]=oldArray[i];
}
return newArr;
}

/**
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
* max = 1, 则返回空数组 []
* @param max
* @return
*/
public int[] fibonacci(int max){
int first=1;
int second=1;
int[] arr=new int[2];
if(max==1){
arr=new int[0];
}
if(max==2){
arr[0]=1;
arr[1]=1;
}
if(max>2){
arr[0]=1;
arr[1]=1;
while(second<max){

int temp;
temp=second;
second=second+first;
first=temp;
if(second<max){
arr=grow(arr,1);
arr[arr.length-1]=second;
}

}
}


return arr;
}

/**
* 返回小于给定最大值max的所有素数数组
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
* @param max
* @return
*/
public int[] getPrimes(int max){
int[] arr=new int[max];
int size=0;
for(int i=2;i<max;i++){ //从2开始一次遍历到最大数max
boolean flag=false;

for(int j=2;j<i;j++){
if(i%j==0){ //存在公约数,跳出。
flag=true;
break;
}
}
if(!flag){//不存在公约数
System.out.println(i);
arr[size]=i;
size++;
}
}
int[] newArr=removeZero(arr);
return newArr;
}

/**
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
* @param max
* @return
*/
public int[] getPerfectNumbers(int max){

int[] arr=new int[10];
int size=1;
arr[0]=1;

for(int i=1;i<max;i++){

int sum=0;
for(int j=1;j<i;j++){ //获取一个数除其本身全部的因数。
if(i%j==0){ //为当前数的因数.
sum=sum+j; //将当前的因数相加。
}
}

if(sum==i){
arr[size]=i;
size++;
}


}
int[] a=removeZero(arr);
return a;
}

/**
* 用seperator 把数组 array给连接起来
* 例如array= [3,8,9], seperator = "-"
* 则返回值为"3-8-9"
* @param array
* @param s
* @return
*/
public String join(int[] array, String seperator){
String a="";
for(int i=0;i<array.length;i++){
if(i<(array.length-1)){
a=a+""+array[i]+seperator;
}
else{
a=a+""+array[i];
}
}
return a;
}








//over
}
63 changes: 63 additions & 0 deletions group10/3314793852/second/src/com/coderising/array/Test.java
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package com.coderising.array;

import java.util.Arrays;

public class Test {

public static void main(String[] args) {
ArrayUtil a=new ArrayUtil();


// int[] arr={1,2,3,5,6};
// a.reverseArray(arr);//结果:6,5,3,2,1

//
// int[] arr={0,2,8,0,8,6,0,5,10};
// int[] newArr=a.removeZero(arr);
// for(int i=0;i<newArr.length;i++){
// System.out.println(newArr[i]);
// }
//结果2,8,8,6,5,10


// int[] arr1={1,3,4,8};
// int[] arr2={2,3,5,7};
// int[] arr3=a.merge(arr1, arr2);
//
// System.out.println(Arrays.toString(arr3));

//
//
// int[] arr={1,2,3,4};
// int[] newArr=a.grow(arr, 10);
// System.out.println(Arrays.toString(newArr));


// int[] arr=a.fibonacci(8);
// System.out.println(Arrays.toString(arr));


// int[] arr=a.getPrimes(35);
// System.out.println(Arrays.toString(arr));


// int[] arr=a.getPerfectNumbers(1000);
// System.out.println(Arrays.toString(arr));
// 1, 6, 28, 496

//
// int[] arr={1,2,3,4};
// String seperator="#";
// String re=a.join(arr, seperator);
// System.out.println(re);
// 1#2#3#4





//结束
}

}
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