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fix descriptions in 1.3 and 1.4
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sean-fitzpatrick committed Oct 2, 2024
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18 changes: 9 additions & 9 deletions ptx/sec_limit_analytically.ptx
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<image width="47%">
<description>
<p>
Graph illustrating the squeeze theorem. There are three functions, <m>h(x)</m>,
An illustration of the squeeze theorem. There are graphs of three functions shown, labelled <m>h(x)</m>,
<m>g(x)</m>, and <m>f(x)</m>. On the <m>y</m>axis, there is a marker at <m>y = 4</m>,
labeled <m>L</m> and on the <m>x</m>axis there is a marker at <m>x = 5</m>, labeled
<m>c</m>.
</p>
<p>
For all values of <m>x \leq c</m> <m>f(x) \leq L</m> and <m>h(x) \geq L</m>.
For all values of <m>x</m> <m>f(x) \leq g(x) \leq h(x)</m>, that is, the line
of the function <m>g(x)</m> is between the lines of the functions <m>g(x)</m>
For all values of <m>x</m> <m>f(x) \leq g(x) \leq h(x)</m>, that is, the graph
of the function <m>g(x)</m> lies between the graphs of the functions <m>g(x)</m>
and <m>f(x)</m>.
</p>
<p>
The graph shows that where <m>x = c</m>, <m>f(x)</m> and <m>h(x)</m> converge
The image shows that where <m>x = c</m>, <m>f(x)</m> and <m>h(x)</m> converge
on <m>y = L = 4</m>. Because <m>f(x) \leq g(x) \leq h(x)</m>, we can extrapolate
that <m>\lim\limits_{x\to \c} g(x) = L</m> too.
</p>
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<image width="47%">
<description>
<p>
Graph of the linear equation <m>(x^1-1)/(x-1)</m>, shows the function with
the <m>y</m> interval <m>0</m> to <m>3</m> and <m>x</m> interval <m>0</m>
to <m>2</m>. The function has a <m>y</m> intercept at <m>y = 1</m>, and
is undefined at <m>x = 1</m>. The graph has a positive slope.
Graph of the function <m>(x^2-1)/(x-1)</m>, showing the region with
<m>y</m> from <m>0</m> to <m>3</m> and <m>x</m> from <m>0</m>
to <m>2</m>. The graph is a straight line, with slope 1 and a <m>y</m> intercept at <m>y = 1</m>,
except for a hole at the point <m>(1,2)</m>, since the function is undefined at <m>x = 1</m>.
</p>
</description>
<shortdescription>
Graph of the polynomial x squared minus 1 divided by the polynomial x minus 1.
Is undefined at x = 1.
It is the same as the line y=x+1, except that it is undefined at x = 1.
</shortdescription>
<latex-image label="img_limitxplus1">
\begin{tikzpicture}
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56 changes: 28 additions & 28 deletions ptx/sec_limit_onesided.ptx
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<p>
Graph of the piecewise function
<m>f(x) = \begin{cases} x \amp 0\leq x\leq 1 \\ 3-x \amp 1\lt x\lt 2 \end{cases}</m>.
There are two lines,
one with a positive slope and the other with a negative slope.
There are two line segments: for <m>0\leq x\leq 1</m> we have a line segment
with positive slope, and for <m>1\lt x\lt 2</m> we have a line segment with negative slope.
</p>
<p>
The line with a positive slope starts at the point <m>(0, 0)</m>
and ends at <m>(1, 1)</m>. The line with a negative slope starts
The line segment with a positive slope starts at the point <m>(0, 0)</m>
and ends at <m>(1, 1)</m>. The line segment with a negative slope starts
at <m>(1, 2)</m> and ends at <m>(2, 1)</m>.
</p>
<p>
The start and end points of the line with a positive slope
are solid dots, indicating that the function is defined
at those points. The start and end points of the line
with a negative slope are hollow dots. This tells us that
the function is undefined for <m>x = 1</m> when going right
to left and <m>x = 2</m> is undedined as well. Because the
function is defined at <m>x = 1</m> on the line with a positive
slope, but is undefined at <m>x = 1</m> on the other line, we can
tell the function <m>f</m> has a one-sided limit as <m>x</m>
approaches <m>1</m>.
The start and end points of the line segment with a positive slope
are solid dots, indicating that those points are part of the graph.
The start and end points of the line segment
with a negative slope are hollow dots.
This tells that although the second line segment gets arbitrarily close
to the points <m>(1,2)</m> and <m>(2,1)</m>, these points are not part of the graph.
</p>

<p>
Since <m>f(x)</m> is close to <m>1</m> when <m>x</m> is close to 1, but <m>x\lt 1</m>,
while <m>f(x)</m> is close to <m>2</m> when <m>x</m> is close to 1, but <m>x\gt 1</m>,
we can conclude that the left and right hand limits are different.
</p>
</description>
<shortdescription>
Graph of a piecewise function that has only a left sided limit as x
approaches 1.
Graph of a piecewise function that has different left and right hand limits when x=1.
</shortdescription>
<latex-image label="img_onesided1">
\begin{tikzpicture}
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<description>
<p>
Graph of <m>f</m> from <xref ref="ex_onesideb"/>.
There are
two lines shown,
the first starts at the point <m>0, 2</m> and ends at
<m>(1, 1)</m>. The second start at <m>(1, 1)</m> and ends
at <m>(2, 0)</m>. Both lines have a negative slope and are
undefined at their start and end points, which are marked with
hollow dots. The first line is straight, but the second has a
small upward curve to it.
The graph consists of two parts.
The first part is a line that starts at the point <m>(0, 2)</m> and ends at
<m>(1, 1)</m>. The second part is a curve that starts at <m>(1, 1)</m> and ends
at <m>(2, 0)</m>.
The points <m>(0,2)</m>, <m>(1,1)</m>, and <m>(2,0)</m> are all marked with hollow dots,
indicating that although the graph gets close to these points, they are not part of the graph.
</p>
<p>
The graph may be undefined for <m>x = 1</m>, but since
the equation has a left and right limit, there for
<m>f(x)</m> has a limit as <m>x</m> approaches <m>1</m>.
The function is undefined for <m>x = 1</m>,
but the graph shows that <m>f(x)</m> approaches the same value (namely, 1)
from both the left and the right, allowing us to conclude that <m>\lim_{x\to 1}f(x)</m> exists,
and is equal to 1.
</p>
</description>
<shortdescription>
Graph of the piecewise function from the previous example.
Graph of a piecewise-defined function. It is undefined when x=1, but has a limit at this point.
</shortdescription>
<latex-image label="img_onesidedb">
\begin{tikzpicture}[declare function = {func(\x) = (\x &lt; 1) * (2 - x) + (\x &gt; = 1) * ((x - 2)^2);}]
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