Revise ruby valid logic to one line #79
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dav1a1223
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JulienBreux
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Oct 5, 2016
| return false unless valid_email?(email) | ||
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| !blacklisted?(email) | ||
| return valid_email?(email) && !blacklisted?(email) |
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valid_email?(email) && !blacklisted?(email)| return false if email.nil? | ||
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| email =~ EMAIL_REGEX | ||
| return !email.nil? && !!(email =~ EMAIL_REGEX) |
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!email.nil? && !!(email =~ EMAIL_REGEX)| return false unless valid_email?(email) | ||
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| !blacklisted?(email) | ||
| return valid_email?(email) && !blacklisted?(email) |
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valid_email?(email) && !blacklisted?(email)| return false if email.nil? | ||
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| email =~ EMAIL_REGEX | ||
| return !email.nil? && !!(email =~ EMAIL_REGEX) |
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!email.nil? && !!(email =~ EMAIL_REGEX)
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Hello @dav1a1223, as @JulienBreux said, just remove the return and I will accept this PR :) |
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OK, it's done. @FGRibreau @JulienBreux thanks a lot !! |
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@dav1a1223 nice work, released in v3.0.16 :) |
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Dear @FGRibreau ,
When I use this handy gem and read the source code,
I found the logic of
valid?andvalid_email?a little complex.So I took a look at
.pyand revise the logic to one line.Hoping that make it easier to understand :)
I'm a beginner to contribute open source, please give me your advice. :)
Thx a lot!!