Avoid unalias()
for matching Array{T}
when broadcasting
#52286
Closed
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It would be good to some review of the reasoning here.
I am assuming that:
Base.mightalias
considers twoArray{T}
to be aliased iff they have the same base pointer in memorybroadcast!(f, A, ..., A, ...)
enforces that the two arrays have the same dimensionsThis implies that when we do an
unaliascopy()
for arrays of the same type, the arrays were aligned element-for-element in memory anyway, which is exactly the case where it is safe to not make a defensive copy due to the traversal mentioned just above.