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Weierstraß theorem: let be and then instead of so that
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legeartisgames authored Dec 21, 2024
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Expand Up @@ -24,8 +24,7 @@ We say that the problem has a solution if the budget set **is not empty**: $x^*

### Extreme value (Weierstrass) theorem

Let $S \subset \mathbb{R}^n$ be a compact set and $f(x)$ a continuous function on $S$.
So that, the point of the global minimum of the function $f (x)$ on $S$ exists.
Let $S \subset \mathbb{R}^n$ be a compact set, and let $f(x)$ be a continuous function on $S$. Then, the point of the global minimum of the function $f (x)$ on $S$ exists.
:::

![A lot of practical problems are theoretically solvable](goodnews.png){#fig-weierstrass}
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Optimization Problems with Inequality Constraints](https://www.scirp.org/pdf/OJOp_2013120315191950.pdf)
* [On Second Order Optimality Conditions in
Nonlinear Optimization](https://www.ime.usp.br/~ghaeser/secondorder.pdf)
* [Numerical Optimization](https://www.math.uci.edu/~qnie/Publications/NumericalOptimization.pdf) by Jorge Nocedal and Stephen J. Wright.
* [Numerical Optimization](https://www.math.uci.edu/~qnie/Publications/NumericalOptimization.pdf) by Jorge Nocedal and Stephen J. Wright.

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