[expr.ref] Remove redundant bullet #7550
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An id-expression can't denote a type, so specifying that this (impossible) case is ill-formed is not necessary.
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A grammatical "id-expression" might not be an expression, because it has not been "suitably declared". Which is fine, because E2 does not need to be (and sometimes isn't) a valid expression in its own right, for example when E2 names a pseudo-destructor or an overload set. |
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E2is grammatically an id-expression, which can't denote a type.