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myDataStructure #15

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8 changes: 8 additions & 0 deletions group11/542194147/myDataStructure/.classpath
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<?xml version="1.0" encoding="UTF-8"?>
<classpath>
<classpathentry kind="src" path="src"/>
<classpathentry kind="con" path="org.eclipse.jdt.junit.JUNIT_CONTAINER/4"/>
<classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/jdk1.8.0_101"/>
<classpathentry kind="lib" path="E:/jar/dom4j/dom4j/1.6.1/dom4j-1.6.1.jar" sourcepath="D:/maven_lib/dom4j/dom4j/1.6.1/dom4j-1.6.1-sources.jar"/>
<classpathentry kind="output" path="bin"/>
</classpath>
1 change: 1 addition & 0 deletions group11/542194147/myDataStructure/.gitignore
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/bin/
17 changes: 17 additions & 0 deletions group11/542194147/myDataStructure/.project
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<?xml version="1.0" encoding="UTF-8"?>
<projectDescription>
<name>myDataStructure</name>
<comment></comment>
<projects>
</projects>
<buildSpec>
<buildCommand>
<name>org.eclipse.jdt.core.javabuilder</name>
<arguments>
</arguments>
</buildCommand>
</buildSpec>
<natures>
<nature>org.eclipse.jdt.core.javanature</nature>
</natures>
</projectDescription>
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package com.coderising.array;

import java.util.Arrays;

/**
* Array集合工具类
* @author 小摩托
*
*/
public class ArrayUtil {

/**
* 给定一个整形数组a , 对该数组的值进行置换
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
* @param origin
* @return
*/
public int[] reverseArray(int[] origin){
if(origin.length==0){
throw new RuntimeException("数组为空");
}
int[]exchange=new int[origin.length];
for(int i=origin.length-1;i>=0;i--){
exchange[origin.length-1-i]=origin[i];
}
return exchange;
}

/**
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
* {1,3,4,5,6,6,5,4,7,6,7,5}
* @param oldArray
* @return
*/

public int[] removeZero(int[] oldArray){
int exchange[]={};
for(int i=0;i<oldArray.length;i++){
if(oldArray[i]!=0){
int newExchange[]=new int[exchange.length+1];
if(i==0){
newExchange[i]=oldArray[i];
}else{
for(int j=0;j<exchange.length;j++){
newExchange[j]=exchange[j];
}
newExchange[exchange.length]=oldArray[i];
}
exchange=newExchange;
}
}
return exchange;
}

/**
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
* @param array1
* @param array2
* @return
*/

public int[] merge(int[] a1, int[] a2){
for(int i=0;i<a2.length;i++){
int newA1[]=new int [a1.length+1];
for(int k=0;k<a1.length;k++){
newA1[k]=a1[k];
}
newA1[a1.length]=a2[i];
a1=newA1;
}
Arrays.sort(a1);
return a1;
}
/**
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
* 注意,老数组的元素在新数组中需要保持
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
* [2,3,6,0,0,0]
* @param oldArray
* @param size
* @return
*/
public int[] grow(int [] oldArray, int size){
int newArray[]=new int[oldArray.length+size];
for(int i=0;i<newArray.length;i++){
if(i<oldArray.length){
newArray[i]=oldArray[i];
}else{
newArray[i]=0;
}
}
return newArray;
}

/**
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
* max = 1, 则返回空数组 []
* @param max
* @return
*/
public int[] fibonacci(int max){
int i=1;
while(getFibonacci(i)<max){
i++;
}
int fibonacci[]=new int[i];
for(int k=0;k<i;k++){
fibonacci[k]=getFibonacci(k);
}
return fibonacci;
}
private int getFibonacci(int n){
if(n<2){return n;}
if(n==2){return 1;}
else{return getFibonacci(n-1)+getFibonacci(n-2);}
}
/**
* 返回小于给定最大值max的所有素数数组
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
* @param max
* @return
*/
public int[] getPrimes(int max){
int primes[]={};
for(int i=1;i<max;i++){
int j=2;
while(j<i){
if(i%j!=0){
j++;
}else{
break;
}
}
if(j==i){
if(i==2){
int newPrimes[]=new int[primes.length+1];
newPrimes[primes.length]=2;
primes=newPrimes;
}else{
int newPrimes[]=new int[primes.length+1];
for(int k=0;k<primes.length;k++){
newPrimes[k]=primes[k];
}
newPrimes[primes.length]=i;
primes=newPrimes;
}

}
}
return primes;
}

/**
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
* @param max
* @return
*/
public int[] getPerfectNumbers(int max){
int perfect[]={};
int value=0;
for(int i=1;i<max;i++){
for(int j=1;j<i;j++){
if(i%j==0){
value+=j;
}
}
if(i==value){
int newPerfect[]=new int[perfect.length+1];
for(int k=0;k<perfect.length;k++){
newPerfect[k]=perfect[k];
}
newPerfect[perfect.length]=i;
perfect=newPerfect;
}
value=0;
}
return perfect;
}

/**
* 用seperator 把数组 array给连接起来
* 例如array= [3,8,9], seperator = "-"
* 则返回值为"3-8-9"
* @param array
* @param s
* @return
*/
public String join(int[] array, String seperator){
StringBuffer sb=new StringBuffer();
if(array.length==0||array==null){
throw new RuntimeException("数组为空");
}
for(int i=0;i<array.length;i++){
if(array.length==i+1){
sb.append(Integer.valueOf(array[i]));
}else{
sb.append(Integer.valueOf(array[i]).toString()).append(seperator);
}
}
return sb.toString();
}

}
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package com.coderising.array;

import org.junit.Test;

public class ArrayUtilTest {

ArrayUtil al=new ArrayUtil();

@Test
public void testReverseArray(){
int origin[]={1,2,3,4,5,6};
int exchange[]=al.reverseArray(origin);
for(int i=0;i<exchange.length;i++){
System.out.println(exchange[i]);
}

}
@Test
public void testRemoveZero(){
int origin[]={1,0,0,2,3,4,5,0,6,0};
int exchange[]=al.removeZero(origin);
for(int i=0;i<exchange.length;i++){
System.out.println(exchange[i]);
}
}
@Test
public void testJoin(){
int array[]= {3,8,9};
String seperator = "-";
String exchange=al.join(array, seperator);
System.out.println(exchange);
}
@Test
public void testGetPerfectNumbers(){
int max=10000;
int perfect[]=al.getPerfectNumbers(max);
for(int i=0;i<perfect.length;i++){
System.out.println(perfect[i]);
}
}
@Test
public void testGetPrimes(){
int max=3;
int perfect[]=al.getPrimes(max);
for(int i=0;i<perfect.length;i++){
System.out.println(perfect[i]);
}
}
@Test
public void testFibonacci(){
int max=100000;
int fibonacci[]=al.fibonacci(max);
for(int i=0;i<fibonacci.length;i++){
System.out.println(fibonacci[i]);
}
}
@Test
public void testGrow(){
int [] oldArray={2,3,6};
int size=3;
int newArray[]=al.grow(oldArray,size);
for(int i=0;i<newArray.length;i++){
System.out.println(newArray[i]);
}
}
}
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package com.coderising.litestruts;

/**
* 这是一个用来展示登录的业务类, 其中的用户名和密码都是硬编码的。
* @author XMT
*
*/
public class LoginAction{
private String name ;
private String password;
private String message;

public String getName() {
return name;
}

public String getPassword() {
return password;
}

public String execute(){
if("test".equals(name) && "1234".equals(password)){
this.message = "login successful";
return "success";
}
this.message = "login failed,please check your user/pwd";
return "fail";
}

public void setName(String name){
this.name = name;
}
public void setPassword(String password){
this.password = password;
}
public String getMessage(){
return this.message;
}
}
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