Skip to content

Commit

Permalink
Merge pull request #32 from ipk2015/master
Browse files Browse the repository at this point in the history
多线程断点续传下载,LinkedList八道练习题
  • Loading branch information
DonaldY authored Mar 27, 2017
2 parents dcfb83f + ad87a8b commit 6ec3648
Show file tree
Hide file tree
Showing 11 changed files with 725 additions and 12 deletions.
Original file line number Diff line number Diff line change
Expand Up @@ -171,7 +171,18 @@ private static class Node{
* 例如链表为 3->7->10 , 逆置后变为 10->7->3
*/
public void reverse(){

if(null==head){
return;
}
Node tempNode=new Node();
Node currentNode=head.next;
head.next=null;
while(null!=currentNode){
tempNode=currentNode.next;
currentNode.next=head;
head=currentNode;
currentNode=tempNode;
}
}

/**
Expand All @@ -181,16 +192,49 @@ public void reverse(){
*/
public void removeFirstHalf(){

if(null==head){
return;
}
Node tempNode;
int size=size();
size=size/2;
for(int i=0;i<size;i++){
tempNode=head;
head=head.next;
tempNode.next=null;
}
}

/**
* 从第i个元素开始, 删除length 个元素 , 注意i从0开始
* @param i
* @param length
*/
public void remove(int i, int length){

public void remove(int index, int length){
ListUtils.checkIndexInRange(index+length, size());
if(null==head){
return;
}
Node tempNode;
if(index==0){
for(int i=0;i<length;i++){
tempNode=head;
head=head.next;
tempNode.next=null;
}
return;
}
Node startNode=head;
for(int i=0;i<index-1;i++){
startNode=startNode.next;
}
Node endNode=startNode.next;
for(int i=0;i<length;i++){
tempNode=endNode;
endNode=endNode.next;
tempNode.next=null;
}
startNode.next=endNode;
}
/**
* 假定当前链表和list均包含已升序排列的整数
Expand All @@ -200,8 +244,25 @@ public void remove(int i, int length){
* 返回的结果应该是[101,301,401,601]
* @param list
*/
public static int[] getElements(LinkedList list){
return null;
public int[] getElements(LinkedList list){
int[] array=new int[list.size()];
Iterator iterator = list.iterator();
int temp=0,next=0,size=0,oriSize=size();
Node tempNode=head;
while(iterator.hasNext()){
next = (Integer) iterator.next();
if(next>=oriSize){
break;
}
temp=next-temp;
for(int i=0;i<temp;i++){
tempNode=tempNode.next;
}
array[size]=(Integer)tempNode.data;
temp=next;
size++;
}
return array;
}

/**
Expand All @@ -212,25 +273,137 @@ public static int[] getElements(LinkedList list){
*/

public void subtract(LinkedList list){

if(null==head){
return;
}
Iterator iterator = list.iterator();
Node tempNode=head;
Node preNode=head;
Node currentNode=head;
int next,tempData=(Integer)head.data;
boolean isEnd=false;
while(iterator.hasNext()){
next = (Integer) iterator.next();
while(tempData<next){
preNode=currentNode;
currentNode=currentNode.next;
if(null==currentNode){
isEnd=true;
break;
}
tempData=(Integer)currentNode.data;
}
if(isEnd){
break;
}
if(tempData>next){
continue;
}
if(currentNode==head){
head=head.next;
}else{
preNode.next=currentNode.next;
}
tempNode=currentNode;
currentNode=currentNode.next;
tempNode.next=null;
if(null==currentNode){
break;
}
tempData=(Integer)currentNode.data;
}
}

/**
* 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。
* 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同)
*/
public void removeDuplicateValues(){

Node currentNode=head;
Node tempNode=head;
int tempData;
while(null!=currentNode && null!=currentNode.next){
tempData=(Integer)currentNode.data;
if(tempData==(Integer)currentNode.next.data){
if(null!=currentNode.next.next){
tempNode=currentNode.next;
currentNode.next=currentNode.next.next;
tempNode.next=null;
}else{
currentNode.next=null;
}
}else{
currentNode=currentNode.next;
}
}
}

/**
* 已知链表中的元素以值递增有序排列,并以单链表作存储结构。
* 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素)
* 试写一高效的算法,删除表中所有值大于等于min且小于等于max的元素(若表中存在这样的元素)
* @param min
* @param max
*/
public void removeRange(int min, int max){

if(null==head){
return;
}
int size=size();
int headData=(Integer)head.data;
int endData=(Integer)get(size-1);
if(headData>=min && endData<=max){
head=null;
return;
}
if(headData>max || endData<min){
return;
}
int startIndex=searchIndexInRange(min,0,size-1);
if((Integer)get(startIndex)<min){
startIndex++;
}
int endIndex=searchIndexInRange(max,startIndex,size-1);
if(startIndex==0){
for(int i=0;i<endIndex+1;i++){
head=head.next;
}
}else{
Node beforeNode=head;
for(int i=0;i<startIndex-1;i++){
beforeNode=beforeNode.next;
}
Node curNode=beforeNode;
for(int i=startIndex-2;i<endIndex;i++){
curNode=curNode.next;
}
beforeNode.next=curNode;
}
}
/*
* 返回的index所在位的值小于等于arm
* */
private int searchIndexInRange(int arm,int beginIndex,int endIndex){
int tempData=(Integer)get(beginIndex);
if(tempData>=arm){
return beginIndex;
}
tempData=(Integer)get(endIndex);
if(tempData<=arm){
return endIndex;
}
int middleIndex=0;
while(beginIndex<endIndex-1){
middleIndex=(beginIndex+endIndex)/2;
tempData=(Integer)get(middleIndex);
if(tempData<arm){
beginIndex=middleIndex;
}else if(tempData>arm){
endIndex=middleIndex;
}else{
break;
}
}
return middleIndex;
}

/**
Expand All @@ -239,6 +412,31 @@ public void removeRange(int min, int max){
* @param list
*/
public LinkedList rsection( LinkedList list){
return null;
LinkedList armList=new LinkedList();
Node tempNode=head;
if(null==list || list.size()==0){
while(null!=tempNode){
armList.add(tempNode.data);
tempNode=tempNode.next;
}
}else{
Iterator iterator = list.iterator();
Integer next;
Integer data;
while(iterator.hasNext()){
next = (Integer)iterator.next();
while(null!=tempNode){
data = (Integer)tempNode.data;
if(data<next){
armList.add(data);
tempNode=tempNode.next;
}else{
break;
}
}
armList.add(next);
}
}
return armList;
}
}
Loading

0 comments on commit 6ec3648

Please sign in to comment.