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3 tydzień skończony, stworzona struktura dla 4 tygodnia.
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ArcCha committed Mar 18, 2016
1 parent 3404db2 commit fb5cad8
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2 changes: 1 addition & 1 deletion tydzien_03/tydzien_03.tex
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Expand Up @@ -12,4 +12,4 @@
\input{./tydzien_03/zad_12}
\input{./tydzien_03/zad_13}
\input{./tydzien_03/zad_14}
\input{./tydzien_03/zad_15}
\input{./tydzien_03/zad_15}
19 changes: 19 additions & 0 deletions tydzien_03/zad_01.tex
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\medskip
\noindent{\bf Zad. 1}
\medskip

\begin{enumerate}[label=(\alph*)]
\item
$P(A) = \frac{4}{52} P(B) = \frac{13}{52}$

$P(A \cap B) = \frac{1}{52}$

$P(A \cap B) = P(A) * P(B)$ są niezależne.

\item
$P(A) = \frac{16}{52} P(B) = \frac{13}{52}$

$P(A) * P(B) = \frac{1}{2} * \frac{13}{52} P(A \cap B) = \frac{13}{52}$

$P(A \cap B) \neq P(A) * P(B)$ nie są niezależne.
\end{enumerate}
Binary file added tydzien_03/zad_10.jpg
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9 changes: 9 additions & 0 deletions tydzien_03/zad_10.tex
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\medskip
\noindent{\bf Zad. 10}
\medskip

\includegraphics{./tydzien_03/zad_10.jpg}

$P(A) = \frac{\frac{2}{8}\frac{1}{2}}{\frac{2}{3}\frac{1}{2} + \frac{1}{8}\frac{1}{2}}
= \frac{\frac{1}{3}}{\frac{1}{3} + \frac{1}{6}} = \frac{2}{3}i$

3 changes: 0 additions & 3 deletions tydzien_03/zad_14.tex
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$P(III) = P(A \cap B \cap C \cap D \cap E) = 0,1 \cdot 0,2 \cdot 0,3 \cdot 0,4 \cdot 0,5 = 0,0012
$


\end{document}

12 changes: 7 additions & 5 deletions tydzien_03/zad_15.tex
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\noindent{\bf Zad. 15}
\medskip

1.\\
1.

$$
|A| = {6\choose2}\\
|\Omega| = {10\choose 6}\\
P(A) = \frac{{6\choose2}}{{10\choose 6}} = \frac{\frac{6!}{2!(6-2)!}}{\frac{10!}{6!(10-6)!}}
= \frac{6!}{2!4!}\cdot\frac{6!4!}{10!} = \frac{3\cdot4\cdot5\cdot6}{1}\cdot\frac{1}{7\cdot8\cdot9\cdot10}=\\
=\frac{1\cdot1\cdot1\cdot6}{7\cdot2\cdot3\cdot2}=\frac{1}{7\cdot2}=\frac{1}{14}\approx7,143\%
\\
$$
\\2\\

2

$$
|B|={6\choose2}\\
|B|={6\choose2}
$$


$$
|\Omega|={6\choose2}+{6\choose3}+{6\choose4}+{6\choose5}\\
P(B) = \frac{{6\choose2}}{{6\choose2}+{6\choose3}+{6\choose4}+{6\choose5}}=
\frac{\frac{5\cdot6}{2}}{\frac{6!}{2!4!}+\frac{6!}{3!3!}+\frac{6!}{4!2!}+\frac{6!}{5!}}=\\
\frac{15}{15+\frac{4\cdot5\cdot6}{2\cdot3}+15+6}
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14 changes: 14 additions & 0 deletions tydzien_04/tydzien_04.tex
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\input{./tydzien_04/zad_01}
\input{./tydzien_04/zad_02}
\input{./tydzien_04/zad_03}
\input{./tydzien_04/zad_04}
\input{./tydzien_04/zad_05}
\input{./tydzien_04/zad_06}
\input{./tydzien_04/zad_07}
\input{./tydzien_04/zad_08}
\input{./tydzien_04/zad_09}
\input{./tydzien_04/zad_10}
\input{./tydzien_04/zad_11}
\input{./tydzien_04/zad_12}
\input{./tydzien_04/zad_13}
\input{./tydzien_04/zad_14}
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7 changes: 4 additions & 3 deletions zadania_rozwiazania.tex
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\usepackage{tikz}
\usetikzlibrary{trees,shapes,backgrounds}
\usepackage{multicol}

\usepackage{enumitem}


\def\B{\mathcal{B}}
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\def\w{\omega}
\def\dom{\mathrm{dom}}

\includeonly{./tydzien_03/tydzien_03}
\includeonly{./tydzien_04/tydzien_04}

\begin{document}

Expand All @@ -60,5 +60,6 @@
\include{./tydzien_01/tydzien_01}
\include{./tydzien_02/tydzien_02}
\include{./tydzien_03/tydzien_03}
\include{./tydzien_04/tydzien_04}

\end{document}
\end{document}

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